Skip to main content

Digital Design Interview Questions - 4

1. Design 2 input AND, OR, and EXOR gates using 2 input NAND gate.
Answer

2. Design a circuit which doubles the frequency of a given input clock signal.
Answer

3. Implement a D-latch using 2x1 multiplexer(s).
Answer

4. Give the excitation table of a JK flip-flop.
Answer

5. Give the Binary, Hexadecimal, BCD, and Excess-3 code for decimal 14.
Answer

6. What is race condition?
Answer

7. Give 1's and 2's complement of 19.
Answer

8. Design a 3:6 decoder.
Answer

9. If A*B=C and C*A=B then, what is the Boolean operator * ?
Answer

10. Design a 3 bit Gray Counter.
Answer

Comments

Popular posts from this blog

Digital Design Interview Questions - All in 1

1. How do you convert a XOR gate into a buffer and a inverter (Use only one XOR gate for each)?
Answer



2. Implement an 2-input AND gate using a 2x1 mux.
Answer



3. What is a multiplexer?
Answer

A multiplexer is a combinational circuit which selects one of many input signals and directs to the only output.

4. What is a ring counter?
Answer

A ring counter is a type of counter composed of a circular shift register. The output of the last shift register is fed to the input of the first register. For example, in a 4-register counter, with initial register values of 1100, the repeating pattern is: 1100, 0110, 0011, 1001, 1100, so on.

5. Compare and Contrast Synchronous and Asynchronous reset.
Answer

Synchronous reset logic will synthesize to smaller flip-flops, particularly if the reset is gated with the logic generating the d-input. But in such a case, the combinational logic gate count grows, so the overall gate count savings may not be that significant. The clock works as a filter for small reset gl…

Gate-Level Modeling

>> Introduction
>> Gate Primitives
>> Delays
>> Examples


Introduction

In Verilog HDL a module can be defined using various levels of abstraction. There are four levels of abstraction in verilog. They are:
Behavioral or algorithmic level: This is the highest level of abstraction. A module can be implemented in terms of the design algorithm. The designer no need to have any knowledge of hardware implementation.Data flow level: In this level the module is designed by specifying the data flow. Designer must how data flows between various registers of the design.Gate level: The module is implemented in terms of logic gates and interconnections between these gates. Designer should know the gate-level diagram of the design.Switch level: This is the lowest level of abstraction. The design is implemented using switches/transistors. Designer requires the knowledge of switch-level implementation details.
Gate-level modeling is virtually the lowest-level of abstraction, because t…

Synchronous Reset vs. Asynchronous Reset

Why Reset?

A Reset is required to initialize a hardware design for system operation and to force an ASIC into a known state for simulation.

A reset simply changes the state of the device/design/ASIC to a user/designer defined state. There are two types of reset, what are they? As you can guess them, they are Synchronous reset and Asynchronous reset.

Synchronous Reset

A synchronous reset signal will only affect or reset the state of the flip-flop on the active edge of the clock. The reset signal is applied as is any other input to the state machine.

Advantages:
The advantage to this type of topology is that the reset presented to all functional flip-flops is fully synchronous to the clock and will always meet the reset recovery time.Synchronous reset logic will synthesize to smaller flip-flops, particularly if the reset is gated with the logic generating the d-input. But in such a case, the combinational logic gate count grows, so the overall gate count savings may not be that significant…